EE-361

Introduction to AC/DC Converters (Rectifiers)

Ozan Keysan

keysan.me

Office: C-113 • Tel: 210 7586

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Rectifiers (AC/DC) Converters

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Single-Phase Diode Rectifier

Drawing Drawing

Commercial Bridge Rectifiers

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Single Phase Half-Wave Rectifier

Drawing

More info

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Single Phase Full-Wave Rectifier

Drawing

More info

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Single Phase Full-Wave Rectifier

Drawing

Let's calculate the average output DC voltage.

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Average output voltage

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Single Phase Full Bridge RectifierAverage Output VoltageVDC=2√2Vph(rms)π=0.9Vph(rms)8 / 15

Single Phase Full Bridge RectifierAverage Output VoltageVDC=2√2Vph(rms)π=0.9Vph(rms)For 230V AC voltage, VDC=207V8 / 15

Three Phase Full-Wave (Bridge) Rectifier

Drawing

More info

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Three Phase Full-Wave (Bridge) Rectifier

Drawing

Output voltage jumps between line-to-line voltages, whichever has the maximum magnitude

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3-Phase Full Wave (Bridge) Rectifier

Six possible line-to-line voltages

Drawing

Output voltage jumps between line-to-line voltages, whichever has the maximum magnitude

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3-Phase Full Wave (Bridge) RectifierAverage Output Voltage?12 / 15

3-Phase Full Wave (Bridge) RectifierAverage Output Voltage?VDC=3√2Vl−l(rms)π=1.35Vl−l(rms)13 / 15

3-Phase Full Wave (Bridge) RectifierAverage Output Voltage?VDC=3√2Vl−l(rms)π=1.35Vl−l(rms)For 230V AC voltage (i.e. 400 V(l-l):VDC=540V13 / 15

Extra Material for Curious Students

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You can download this presentation from: keysan.me/ee361

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EE-361

Introduction to AC/DC Converters (Rectifiers)

Ozan Keysan

Rectifiers (AC/DC) Converters

Single-Phase Diode Rectifier

Commercial Bridge Rectifiers

Single Phase Half-Wave Rectifier

Single Phase Full-Wave Rectifier

Single Phase Full-Wave Rectifier

Let's calculate the average output DC voltage.

Average output voltage

Single Phase Full Bridge Rectifier

Average Output Voltage

VDC=2√2Vph(rms)π=0.9Vph(rms)V_{DC}= \dfrac{2\sqrt{2} V_{ph(rms)}}{\pi} = 0.9 V_{ph(rms)}

Single Phase Full Bridge Rectifier

Average Output Voltage

VDC=2√2Vph(rms)π=0.9Vph(rms)V_{DC}= \dfrac{2\sqrt{2} V_{ph(rms)}}{\pi} = 0.9 V_{ph(rms)}

For 230V AC voltage, VDC=207VV_{DC}=207V

Three Phase Full-Wave (Bridge) Rectifier

Three Phase Full-Wave (Bridge) Rectifier

Output voltage jumps between line-to-line voltages, whichever has the maximum magnitude

3-Phase Full Wave (Bridge) Rectifier

Six possible line-to-line voltages

Output voltage jumps between line-to-line voltages, whichever has the maximum magnitude

3-Phase Full Wave (Bridge) Rectifier

Average Output Voltage?

3-Phase Full Wave (Bridge) Rectifier

Average Output Voltage?

VDC=3√2Vl−l(rms)π=1.35Vl−l(rms)V_{DC}= \dfrac{3\sqrt{2} V_{l-l(rms)}}{\pi} = 1.35 V_{l-l(rms)}

3-Phase Full Wave (Bridge) Rectifier

Average Output Voltage?

VDC=3√2Vl−l(rms)π=1.35Vl−l(rms)V_{DC}= \dfrac{3\sqrt{2} V_{l-l(rms)}}{\pi} = 1.35 V_{l-l(rms)}

For 230V AC voltage (i.e. 400 V(l-l):

VDC=540VV_{DC}=540 V

Extra Material for Curious Students

You can download this presentation from: keysan.me/ee361

Rectifiers (AC/DC) Converters

Help

$V_{DC}= \dfrac{2\sqrt{2} V_{ph(rms)}}{\pi} = 0.9 V_{ph(rms)}$

$V_{DC}= \dfrac{2\sqrt{2} V_{ph(rms)}}{\pi} = 0.9 V_{ph(rms)}$

For 230V AC voltage, $V_{DC}=207V$

$V_{DC}= \dfrac{3\sqrt{2} V_{l-l(rms)}}{\pi} = 1.35 V_{l-l(rms)}$

$V_{DC}= \dfrac{3\sqrt{2} V_{l-l(rms)}}{\pi} = 1.35 V_{l-l(rms)}$

$V_{DC}=540 V$